hey all,given 192.168.2.1 and 192.168.1.1that is considered2 different networks right? because of the 3rd byte being different? so 2computerseach one having either of the addresses above wouldn't be able to talk right?thanks,rodchar

rodchar said: given 192.168.2.1 and 192.168.1.1that is considered2 different networks right? because of the 3rd byte being different? so 2computerseach one having either of the addresses above wouldn't be able to talk right?Based on the given, we cannot really tell if these two machines belong to the same network (unless you are implying that theseare [classful] class C addresses). You have to provide the subnet mask before we can conclude that these two machines are on the same network or not. For example, if the subnet mask is 255.255.252.0 (one of the many possible subnet masks), then these two machines are on the same network. If the subnet mask is 255.255.254.0, then they are on different networks.Just to add, even if these machines are on different networks, if you configured routing on your infrastructure, they should be able to talk to each other.Salvador Manaois III MCSE MCSA CEH MCITP | Enterprise/Server Admin Bytes & Badz : http://badzmanaois.blogspot.com

Yes and no. It depends on the netmask. With the standard subnet mask of 255.255.255.0 they are in different IP subnets. 192.168.2.1 and 192.168.1.1 are in the same subnet if the netmask is 22 bits (255.255.252) or less. They are in different subnets if the subnet mask is 24 bits (255.255.255.0). The length of the subnet mask defines what part of the address is used as the subnet address. What is left over identifies the machine with in the subnet. With a 24-bit subnet mask, 192.168.1.1 is machine 1 in subnet 192.168.1.0/24 and 192.168.2.1 is machine one in subnet 192.168.2.0/24 . If you look at the 10.0.0.0 set of private addresses, thedefault subnet mask is eight bits (255.0.0.0) and the subnet is 10.0.0.0/8 . You can haveabout 16 million machines in that subnet (nearly 256 cubed). It all looks a bit confusing in decimal notation but makes a lot of sense if you look at the binary (which is what the machine does)! Bill

sorry for delay, thanks for the insight.i'm still trying to soak it in...