OS: Windows 2003 Setup: LAN IP Address: 192.168.0.1 Subnet: 255.255.0.0 We are teaching trainers and technicians on how to configure these systems as standalones LAN. The argument I am making is the subnet mask of 255.255.0.0 for IP Address 192.168.0.1 is incorrect. In my opinion it should be 255.255.255.0 per TCP/IP. Can someone else advice what would be the correct subnet for 192.168.0.1? Thanks

the correct subnet mask would be 255.255.255.0 for 192.168.0.1 subnet because its a class C address and 2 octates are reserverd for the network subnet and 1 for the host subnet. http://www.virmansec.com/blogs/skhairuddin

Hi, Thanks for the post. 192.168.0.0/16 (192.168.0.0, 255.255.0.0) Allows the following range of valid IPv4 unicast addresses: 192.168.0.1 to 192.168.255.254. The 192.168.0.0/16 address prefix has 16 host bits that you can use for any addressing scheme within a private organization. For more information, please take the time to check RFC1918. Thanks, Miles Please remember to click “Mark as Answer” on the post that helps you, and to click “Unmark as Answer” if a marked post does not actually answer your question. This can be beneficial to other community members reading the thread.

Hi, Please feel free to me know if the information was helpful to you. Thanks, MilesPlease remember to click Mark as Answer on the post that helps you, and to click Unmark as Answer if a marked post does not actually answer your question. This can be beneficial to other community members reading the thread.