I have a business need to create a report by query data from a MS SQL 2008 database and display the result to the users on a web page. The report initially has 6 columns of data and 2 out of 6 have JSON
data so the users request to have those 2 JSON columns parse into 15 additional columns (first JSON column has 8 key/value pairs and the second JSON column has 7 key/value pairs). Here what I have done so far:
I found a table value function (fnSplitJson2) from this link
http://www.sqlservercentral.com/articles/JSON/68128/. Using this function I can parse a column of JSON data into a table. So when I use the function above against the first column (with JSON data) in my query (with CROSS APPLY) I got the right data
back the but I got 8 additional rows of each of the row in my table. The reason for this side effect is because the function returned a table of 8 row (8 key/value pairs) for each json string data that it parsed.
1. First question: How do I modify my current query (see below) so that for each row in my table i got back one row with 19 columns.
SELECT A.ITEM1,A.ITEM2,A.ITEM3,A.ITEM4, B.*
FROM PRODUCT A
CROSS APPLY fnSplitJson2(A.ITEM5,NULL) B
If updated my query (see below) and call the function twice within the CROSS APPLY clause I got this error: "The multi-part identifier "A.ITEM6" could be be bound.
2. My second question: How to i get around this error?
SELECT A.ITEM1,A.ITEM2,A.ITEM3,A.ITEM4, B.*, C.*
FROM PRODUCT A
CROSS APPLY fnSplitJson2(A.ITEM5,NULL) B, fnSplitJson2(A.ITEM6,NULL) C
Thank you so much in advance for your help.
I am using Microsoft SQL Server 2008 R2 version. Windows 7 desktop.
- Edited by dvnandover Wednesday, April 29, 2015 7:53 PM