I need to create a SFTP send port where I should get the output file name and extension same as that of the incoming filename

I had set the filename in the send port as "%SourceFileName%" but this did not work.

I have also assigned the input filename (without extension) in a variable in orchestartion. Is there any way i could get the output filename and extension same as that of the incoming message?

Any help would be much appreciated

• Edited by ReKi111 5 hours 7 minutes ago

Hi,

The %SourceFileName% macro maps to the context property BTS.ReceiveFileName that travels with your message in the context. So in order for this macro to work in a send port the message that is going out needs to have this BTS.ReceiveFileName property on the context. You probably creating a new message in your orchestration and sending that out. The new message does not have the property on its context which makes it fail. Use a message assignment shape in your orchestration to set the context property for the message going out:

MyMessage(BTS.ReceiveFileName) = OrigMessage(BTS.ReceiveFileName);

Then %SourceFileName% macro will work at send port.

Rachit

Few things:

1. You can only get the original file name from the File Adapter or FTP Adapter.
2. They will populate the FILE.ReceivedFileName property with the full path so you will have to extract just the file name.
3. You have to preserve this value through the entire process, including all in between Orchestrations.
4. On the final outbound message, you have re-set, does not have to be Promoted, FILE.ReceivedFileName again to make it available through the %SourceFileName% macro.

MyOutgoingMessage(FILE.ReceivedFileName) = MyOriginalFilenameVariable;

Note: The property name is FILE.ReceivedFileName.

• Edited by Johns-305 [boatseller] 17 hours 15 minutes ago
• Proposed as answer by M.R.Ashwin PrabhuMVP 17 hours 1 minutes ago

In addition to what others have said here, in your Orchestration in Message assignment shape (while constructing the outbound message) use the following code directly.

msgOut(FILE.ReceivedFileName) = System.IO.Path.GetFileNameWithoutExtension(msgIn(FILE.ReceivedFileName));

Hi Reki,

By Default file Adapter will not promote the ReceivedFile Name property(It will be added to context only).

Promote ReceivedFile Name property in your receive pipleline then user %SourceFileName% macro in send pipeline .

It will give you the result.

Thanks &Regards,

Ammu.



Promote ReceivedFile Name property in your receive pipleline then user %SourceFileName% macro in send pipeline .

For clarity, FILE.ReceivedFileName does not have to be Promoted to be used with the %SourceFileName% macro.  It simply must exist on the Context.

the adapter used at send port is SFTP. I have got the filename using FILE.ReceivedFileName, how do i proceed further?

the adapter used at send port is SFTP. I have got the filename using FILE.ReceivedFileName, how do i proceed further?