Probably pretty simple but I need help. 192.168.1.110/25 what is the network ID? What is the formula to figure this out. I searched the web for 1.5 hours finding calculators that would do it but nothing other than that.

Kem IP address 192.168.1.110/25 belongs to Class C address. 192.168.1.110 - IP address /25 - Subnet i.e 255.255.255.128 , That means you will be having 2 subnets in ths subnets 1.192.168.1.1 to 192.168.1.126 2.192.168.1.127-192.168.1.254 Below the link which explains about this clearly http://www.cisco.com/en/US/docs/security/pix/pix51/configuration/guide/subnets.pdf Tips and Tricks to calculate subnets http://www.ehow.com/how_6672674_calculate-subnetting.html Online subnet calculator, http://www.subnet-calculator.com/subnet.php?net_class=C About subnetting, http://www.scribd.com/doc/2158531/How-to-subnet-in-your-head Hope this will help. Regards, _Prashant_ MCSA|MCITP SA|Microsoft Exchange 2003 Blog - http://prashant1987.wordpress.com Disclaimer: This posting is provided AS-IS with no warranties/guarantees and confers no rights. Email-giteepag@yahoo.co.in

Here are some of the references which should help you Quick and Easy Subnetting on Routing, Switching and Network Design Relationship http://www.dslreports.com/faq/8426 Subnetting http://technet.microsoft.com/en-us/library/cc958834.aspx How to calculate Subnet mask, Calculate Variable Length Subnet Mask (VLSM) http://ccnaanswers-khim.blogspot.in/2011/02/how-to-calculate-subnet-mask-calculate.html Calculating Subnet Masks http://www.networkclue.com/routing/tcpip/calculating-masks.aspxIf it looks good, Eat it ! Likewise, If you don't know the answers, don't hesitate to ask questions !! This posting is provided "AS IS" with no warranties or guarantees and confers no rights. About Me !!!

Thank you. Your response got me thinking. Using your response I came up with an example below. I will follow up on the links to both response tomorrow. I took an address that was easier to manage: 192.168.1.110/26 first I figured out the root: 192.168.1.0 class C Then I divide it up based upon /26 Subnet1: 192.168.1.0 - 192.168.1.63 (network ID 192.168.1.0) Subnet2: 192.168.1.64 - 192.168.1.127 (network ID 192.168.1.64) Subnet3: 192.168.1.128 - 192.168.1.191 (network ID 192.168.1.128) Subnet4: 192.168.1.192 - 192.168.1.255 (network ID 192.168.1.192) No addresses left over The network ID of the address 192.168.1.110/26 is 192.168.1.64 because if falls between the 192.168.1.64 and 192.168.1.127. Thank You.

Thank you for the links. I will follow up with them tomorrow. My brain is dead right now.

You are welcome....MCSA|MCITP SA|Microsoft Exchange 2003 Blog - http://prashant1987.wordpress.com Disclaimer: This posting is provided AS-IS with no warranties/guarantees and confers no rights. Email-giteepag@yahoo.co.in

Thanks for time and efforts.Jeff Ren TechNet Community Support beneficial to other community members reading the thread.