Find Network ID
Probably pretty simple but I need help.
192.168.1.110/25 what is the network ID? What is the formula to figure this out. I searched the web for 1.5 hours finding calculators that would do it but nothing other than that.
April 12th, 2012 11:43pm
Kem IP address 192.168.1.110/25 belongs to Class C address.
192.168.1.110 - IP address
/25 - Subnet i.e 255.255.255.128 ,
That means you will be having 2 subnets in ths subnets 1.192.168.1.1 to 192.168.1.126 2.192.168.1.127-192.168.1.254
Below the link which explains about this clearly
http://www.cisco.com/en/US/docs/security/pix/pix51/configuration/guide/subnets.pdf
Tips and Tricks to calculate subnets
http://www.ehow.com/how_6672674_calculate-subnetting.html
Online subnet calculator,
http://www.subnet-calculator.com/subnet.php?net_class=C
About subnetting,
http://www.scribd.com/doc/2158531/How-to-subnet-in-your-head
Hope this will help.
Regards,
_Prashant_
MCSA|MCITP SA|Microsoft Exchange 2003 Blog - http://prashant1987.wordpress.com Disclaimer: This posting is provided AS-IS with no warranties/guarantees and confers no rights. Email-giteepag@yahoo.co.in
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April 13th, 2012 12:22am
Here are some of the references which should help you
Quick and Easy Subnetting on Routing, Switching and Network Design Relationship
http://www.dslreports.com/faq/8426
Subnetting
http://technet.microsoft.com/en-us/library/cc958834.aspx
How to calculate Subnet mask, Calculate Variable Length Subnet Mask (VLSM)
http://ccnaanswers-khim.blogspot.in/2011/02/how-to-calculate-subnet-mask-calculate.html
Calculating Subnet Masks
http://www.networkclue.com/routing/tcpip/calculating-masks.aspxIf it looks good, Eat it ! Likewise, If you don't know the answers, don't hesitate to ask questions !!
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April 13th, 2012 12:26am
Thank you. Your response got me thinking. Using your response I came up with an example below. I will follow up on the links to both response tomorrow.
I took an address that was easier to manage: 192.168.1.110/26
first I figured out the root: 192.168.1.0 class C
Then I divide it up based upon /26
Subnet1: 192.168.1.0 - 192.168.1.63 (network ID 192.168.1.0)
Subnet2: 192.168.1.64 - 192.168.1.127 (network ID 192.168.1.64)
Subnet3: 192.168.1.128 - 192.168.1.191 (network ID 192.168.1.128)
Subnet4: 192.168.1.192 - 192.168.1.255 (network ID 192.168.1.192)
No addresses left over
The network ID of the address 192.168.1.110/26 is 192.168.1.64 because if falls between the 192.168.1.64 and 192.168.1.127.
Thank You.
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April 13th, 2012 1:23am
Thank you for the links. I will follow up with them tomorrow. My brain is dead right now.
April 13th, 2012 1:24am
You are welcome....MCSA|MCITP SA|Microsoft Exchange 2003 Blog - http://prashant1987.wordpress.com Disclaimer: This posting is provided AS-IS with no warranties/guarantees and confers no rights. Email-giteepag@yahoo.co.in
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April 13th, 2012 1:26am
Thanks for time and efforts.Jeff Ren TechNet Community Support beneficial to other community members reading the thread.
May 7th, 2012 2:37am